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AD<
Base>
y(
x)
AD<
Base>
y =
x
y =
x
AD<
Base>
object y
and the assignment operator uses an existing y.
In either case,
y has the same value as x,
and the same dependence on the
independent variables
(y is a
variable
if and only if x is a variable).
const
Type &
x
where Type is
VecAD<
Base>::reference
,
AD<
Base>
,
Base, or
double
.
AD<
Base> &
y
CopyAD.cpp | AD Copy Constructor: Example and Test |
CopyBase.cpp | AD Constructor From Base Type: Example and Test |
Eq.cpp | AD Assignment Operator: Example and Test |