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y =
f.Forward(0,
x)
F : B^n \rightarrow B^m
to denote the
AD function
corresponding to f.
The result of the syntax above is
\[
y = F(x)
\]
(See the FunCheck discussion
for
possible differences between
F(x)
and the algorithm that defined
the operation sequence.)
ADFun<
Base>
f
Note that the ADFun
object f is not const
.
After this call to Forward
, the value returned by
f.size_taylor()
will be equal to one (see size_taylor
).
const
Vector &
x
(see Vector
below)
and its size
must be equal to n, the dimension of the
domain
space for f.
Vector
y
(see Vector
below)
and its value is
F(x)
.
The size of y
is equal to m, the dimension of the
range
space for f.